Base | Representation |
---|---|
bin | 100100111101111000010… |
… | …011110011101010101111 |
3 | 22222212001221122201121220 |
4 | 210331320103303222233 |
5 | 313110111044131343 |
6 | 5223003514554423 |
7 | 351351044554344 |
oct | 44757023635257 |
9 | 8885057581556 |
10 | 2540344130223 |
11 | 89a399042469 |
12 | 350404138a13 |
13 | 155726b43c43 |
14 | 8ad4bc607cb |
15 | 46130922183 |
hex | 24f784f3aaf |
2540344130223 has 8 divisors (see below), whose sum is σ = 3387167694000. Its totient is φ = 1693541659968.
The previous prime is 2540344130113. The next prime is 2540344130231. The reversal of 2540344130223 is 3220314430452.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2540344130223 - 213 = 2540344122031 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2540344130243) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4990198 + ... + 5475651.
It is an arithmetic number, because the mean of its divisors is an integer number (423395961750).
Almost surely, 22540344130223 is an apocalyptic number.
2540344130223 is a deficient number, since it is larger than the sum of its proper divisors (846823563777).
2540344130223 is a wasteful number, since it uses less digits than its factorization.
2540344130223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10546761.
The product of its (nonzero) digits is 69120, while the sum is 33.
Adding to 2540344130223 its reverse (3220314430452), we get a palindrome (5760658560675).
The spelling of 2540344130223 in words is "two trillion, five hundred forty billion, three hundred forty-four million, one hundred thirty thousand, two hundred twenty-three".
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