Base | Representation |
---|---|
bin | 1110110010011000110… |
… | …1011101111011011011 |
3 | 220021201202212012120220 |
4 | 3230212031131323123 |
5 | 13130240244311011 |
6 | 312412315251123 |
7 | 24232310343123 |
oct | 3544615357333 |
9 | 807652765526 |
10 | 254044135131 |
11 | 98815322896 |
12 | 4129aa49aa3 |
13 | 1ac57b94367 |
14 | c41d973c83 |
15 | 691cdab506 |
hex | 3b2635dedb |
254044135131 has 32 divisors (see below), whose sum is σ = 353031610368. Its totient is φ = 162317675520.
The previous prime is 254044135127. The next prime is 254044135171. The reversal of 254044135131 is 131531440452.
It is not a de Polignac number, because 254044135131 - 22 = 254044135127 is a prime.
It is a super-2 number, since 2×2540441351312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 254044135092 and 254044135101.
It is not an unprimeable number, because it can be changed into a prime (254044135171) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13936335 + ... + 13954551.
It is an arithmetic number, because the mean of its divisors is an integer number (11032237824).
Almost surely, 2254044135131 is an apocalyptic number.
254044135131 is a deficient number, since it is larger than the sum of its proper divisors (98987475237).
254044135131 is a wasteful number, since it uses less digits than its factorization.
254044135131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19691.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 254044135131 its reverse (131531440452), we get a palindrome (385575575583).
The spelling of 254044135131 in words is "two hundred fifty-four billion, forty-four million, one hundred thirty-five thousand, one hundred thirty-one".
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