2540500131 has 16 divisors (see below), whose sum is σ = 3685510304. Its totient is φ = 1547265024.

The previous prime is 2540500129. The next prime is 2540500133. The reversal of 2540500131 is 1310050452.

It is an interprime number because it is at equal distance from previous prime (2540500129) and next prime (2540500133).

It is not a de Polignac number, because 2540500131 - 2¹ = 2540500129 is a prime.

It is a super-2 number, since 2×2540500131² = 12908281831222034322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2540500098 and 2540500107.

It is not an unprimeable number, because it can be changed into a prime (2540500133) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 331996 + ... + 339561.

It is an arithmetic number, because the mean of its divisors is an integer number (230344394).

Almost surely, 2^2540500131 is an apocalyptic number.

2540500131 is a deficient number, since it is larger than the sum of its proper divisors (1145010173).

2540500131 is a wasteful number, since it uses less digits than its factorization.

2540500131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 671670.

The product of its (nonzero) digits is 600, while the sum is 21.

The square root of 2540500131 is about 50403.3742025274. The cubic root of 2540500131 is about 1364.4985354909.

Adding to 2540500131 its reverse (1310050452), we get a palindrome (3850550583).

The spelling of 2540500131 in words is "two billion, five hundred forty million, five hundred thousand, one hundred thirty-one".