Base | Representation |
---|---|
bin | 1011100011011000101111… |
… | …10111111101011000001111 |
3 | 10022221201002100002202022120 |
4 | 11301230113313331120033 |
5 | 11312214202304214020 |
6 | 130010542341344023 |
7 | 5231313566564043 |
oct | 561542767753017 |
9 | 108851070082276 |
10 | 25405132101135 |
11 | 810528a840496 |
12 | 2a23827408013 |
13 | 1123903017b67 |
14 | 63b887614023 |
15 | 2e0ca47ed740 |
hex | 171b17dfd60f |
25405132101135 has 16 divisors (see below), whose sum is σ = 40652212807680. Its totient is φ = 13548069972000.
The previous prime is 25405132101133. The next prime is 25405132101221. The reversal of 25405132101135 is 53110123150452.
It is not a de Polignac number, because 25405132101135 - 21 = 25405132101133 is a prime.
It is a super-2 number, since 2×254051321011352 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 25405132101096 and 25405132101105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (25405132101133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 83205991 + ... + 83510760.
It is an arithmetic number, because the mean of its divisors is an integer number (2540763300480).
Almost surely, 225405132101135 is an apocalyptic number.
25405132101135 is a deficient number, since it is larger than the sum of its proper divisors (15247080706545).
25405132101135 is a wasteful number, since it uses less digits than its factorization.
25405132101135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 166726918.
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 25405132101135 its reverse (53110123150452), we get a palindrome (78515255251587).
The spelling of 25405132101135 in words is "twenty-five trillion, four hundred five billion, one hundred thirty-two million, one hundred one thousand, one hundred thirty-five".
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