Base | Representation |
---|---|
bin | 111001110000111111101010… |
… | …010010000100001100011111 |
3 | 1020022112110202110220202122212 |
4 | 321300333222102010030133 |
5 | 231244421222012130030 |
6 | 2300155300540031035 |
7 | 104340623100621602 |
oct | 7160775222041437 |
9 | 1208473673822585 |
10 | 254055541130015 |
11 | 73a4a393832049 |
12 | 245b17ba83247b |
13 | ab9b447531c51 |
14 | 46a44d4b80339 |
15 | 1e5887ac45595 |
hex | e70fea48431f |
254055541130015 has 16 divisors (see below), whose sum is σ = 315383482630080. Its totient is φ = 196233396952320.
The previous prime is 254055541129979. The next prime is 254055541130029. The reversal of 254055541130015 is 510031145550452.
It is a de Polignac number, because none of the positive numbers 2k-254055541130015 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 652574 + ... + 22550763.
It is an arithmetic number, because the mean of its divisors is an integer number (19711467664380).
Almost surely, 2254055541130015 is an apocalyptic number.
254055541130015 is a deficient number, since it is larger than the sum of its proper divisors (61327941500065).
254055541130015 is a wasteful number, since it uses less digits than its factorization.
254055541130015 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23278882.
The product of its (nonzero) digits is 300000, while the sum is 41.
Adding to 254055541130015 its reverse (510031145550452), we get a palindrome (764086686680467).
The spelling of 254055541130015 in words is "two hundred fifty-four trillion, fifty-five billion, five hundred forty-one million, one hundred thirty thousand, fifteen".
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