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254116433 = 1991276967
BaseRepresentation
bin11110010010110…
…00001001010001
3122201011110012202
433021120021101
51010023211213
641114332545
76203645144
oct1711301121
9581143182
10254116433
1112049548a
127112a155
134085426c
1425a6c05b
1517498b58
hexf258251

254116433 has 4 divisors (see below), whose sum is σ = 255393600. Its totient is φ = 252839268.

The previous prime is 254116427. The next prime is 254116453. The reversal of 254116433 is 334611452.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 254116433 - 216 = 254050897 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 254116396 and 254116405.

It is not an unprimeable number, because it can be changed into a prime (254116453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 638285 + ... + 638682.

It is an arithmetic number, because the mean of its divisors is an integer number (63848400).

Almost surely, 2254116433 is an apocalyptic number.

It is an amenable number.

254116433 is a deficient number, since it is larger than the sum of its proper divisors (1277167).

254116433 is a wasteful number, since it uses less digits than its factorization.

254116433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1277166.

The product of its digits is 8640, while the sum is 29.

The square root of 254116433 is about 15941.0298600812. The cubic root of 254116433 is about 633.3993064854.

Adding to 254116433 its reverse (334611452), we get a palindrome (588727885).

The spelling of 254116433 in words is "two hundred fifty-four million, one hundred sixteen thousand, four hundred thirty-three".

Divisors: 1 199 1276967 254116433