25414231113131 has 6 divisors (see below), whose sum is σ = 29563493335740. Its totient is φ = 21783626668356.

The previous prime is 25414231113127. The next prime is 25414231113149. The reversal of 25414231113131 is 13131113241452.

It is not a de Polignac number, because 25414231113131 - 2² = 25414231113127 is a prime.

It is a super-2 number, since 2×25414231113131² (a number of 28 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (25414231110131) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 259328888861 + ... + 259328888958.

It is an arithmetic number, because the mean of its divisors is an integer number (4927248889290).

Almost surely, 2^{25414231113131} is an apocalyptic number.

25414231113131 is a deficient number, since it is larger than the sum of its proper divisors (4149262222609).

25414231113131 is an equidigital number, since it uses as much as digits as its factorization.

25414231113131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 518657777833 (or 518657777826 counting only the distinct ones).

The product of its digits is 8640, while the sum is 32.

Adding to 25414231113131 its reverse (13131113241452), we get a palindrome (38545344354583).

The spelling of 25414231113131 in words is "twenty-five trillion, four hundred fourteen billion, two hundred thirty-one million, one hundred thirteen thousand, one hundred thirty-one".