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2542133551101 = 3847377850367
BaseRepresentation
bin100100111111100010111…
…101111001111111111101
3100000000200122202201121020
4210333202331321333331
5313122242142113401
65223501240254353
7351443303441004
oct44774275717775
910000618681536
102542133551101
118a01271308a1
123508234713b9
1315595079b971
148b07b781c3b
15461d7a8ad36
hex24fe2f79ffd

2542133551101 has 4 divisors (see below), whose sum is σ = 3389511401472. Its totient is φ = 1694755700732.

The previous prime is 2542133551081. The next prime is 2542133551117. The reversal of 2542133551101 is 1011553312452.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2542133551101 - 27 = 2542133550973 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2542133551201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 423688925181 + ... + 423688925186.

It is an arithmetic number, because the mean of its divisors is an integer number (847377850368).

Almost surely, 22542133551101 is an apocalyptic number.

It is an amenable number.

2542133551101 is a deficient number, since it is larger than the sum of its proper divisors (847377850371).

2542133551101 is an equidigital number, since it uses as much as digits as its factorization.

2542133551101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 847377850370.

The product of its (nonzero) digits is 18000, while the sum is 33.

Adding to 2542133551101 its reverse (1011553312452), we get a palindrome (3553686863553).

The spelling of 2542133551101 in words is "two trillion, five hundred forty-two billion, one hundred thirty-three million, five hundred fifty-one thousand, one hundred one".

Divisors: 1 3 847377850367 2542133551101