Base | Representation |
---|---|
bin | 1001011110010100… |
… | …1111010000100101 |
3 | 20120020022221210011 |
4 | 2113211033100211 |
5 | 20202014341240 |
6 | 1100203530221 |
7 | 120010114144 |
oct | 22745172045 |
9 | 6506287704 |
10 | 2543121445 |
11 | 1095586867 |
12 | 5ab829971 |
13 | 316b499b7 |
14 | 1a1a7775b |
15 | ed3e76ea |
hex | 9794f425 |
2543121445 has 4 divisors (see below), whose sum is σ = 3051745740. Its totient is φ = 2034497152.
The previous prime is 2543121379. The next prime is 2543121461. The reversal of 2543121445 is 5441213452.
2543121445 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 343323841 + 2199797604 = 18529^2 + 46902^2 .
It is a cyclic number.
It is not a de Polignac number, because 2543121445 - 221 = 2541024293 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 254312140 + ... + 254312149.
It is an arithmetic number, because the mean of its divisors is an integer number (762936435).
Almost surely, 22543121445 is an apocalyptic number.
It is an amenable number.
2543121445 is a deficient number, since it is larger than the sum of its proper divisors (508624295).
2543121445 is an equidigital number, since it uses as much as digits as its factorization.
2543121445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 508624294.
The product of its digits is 19200, while the sum is 31.
The square root of 2543121445 is about 50429.3708566744. The cubic root of 2543121445 is about 1364.9676753517.
Adding to 2543121445 its reverse (5441213452), we get a palindrome (7984334897).
The spelling of 2543121445 in words is "two billion, five hundred forty-three million, one hundred twenty-one thousand, four hundred forty-five".
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