Base | Representation |
---|---|
bin | 111001110101000000011001… |
… | …000001111000110001111111 |
3 | 1020100111211021211222012102021 |
4 | 321311000121001320301333 |
5 | 231313430301022400210 |
6 | 2300530050345341011 |
7 | 104366552211620533 |
oct | 7165003101706177 |
9 | 1210454254865367 |
10 | 254331203325055 |
11 | 7404629197024a |
12 | 24637111497767 |
13 | abbb43908b01c |
14 | 46b39a5871bc3 |
15 | 1e60b11937bda |
hex | e75019078c7f |
254331203325055 has 8 divisors (see below), whose sum is σ = 305345382656832. Its totient is φ = 203366336882208.
The previous prime is 254331203325029. The next prime is 254331203325163. The reversal of 254331203325055 is 550523302133452.
254331203325055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 254331203325055 - 29 = 254331203324543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12328210884 + ... + 12328231513.
It is an arithmetic number, because the mean of its divisors is an integer number (38168172832104).
Almost surely, 2254331203325055 is an apocalyptic number.
254331203325055 is a deficient number, since it is larger than the sum of its proper divisors (51014179331777).
254331203325055 is a wasteful number, since it uses less digits than its factorization.
254331203325055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24656444465.
The product of its (nonzero) digits is 1620000, while the sum is 43.
The spelling of 254331203325055 in words is "two hundred fifty-four trillion, three hundred thirty-one billion, two hundred three million, three hundred twenty-five thousand, fifty-five".
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