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25434114301 = 142317873587
BaseRepresentation
bin10111101011111111…
…011100100011111101
32102122112202212200101
4113223333130203331
5404042113124201
615403445201101
71560165255511
oct275377344375
972575685611
1025434114301
11a871992582
124b19a00191
13252446069b
141333cac141
159dcd73d01
hex5ebfdc8fd

25434114301 has 4 divisors (see below), whose sum is σ = 25451989312. Its totient is φ = 25416239292.

The previous prime is 25434114287. The next prime is 25434114353. The reversal of 25434114301 is 10341143452.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25434114301 - 213 = 25434106109 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 25434114301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25434114371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8935371 + ... + 8938216.

It is an arithmetic number, because the mean of its divisors is an integer number (6362997328).

Almost surely, 225434114301 is an apocalyptic number.

It is an amenable number.

25434114301 is a deficient number, since it is larger than the sum of its proper divisors (17875011).

25434114301 is a wasteful number, since it uses less digits than its factorization.

25434114301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17875010.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 25434114301 its reverse (10341143452), we get a palindrome (35775257753).

The spelling of 25434114301 in words is "twenty-five billion, four hundred thirty-four million, one hundred fourteen thousand, three hundred one".

Divisors: 1 1423 17873587 25434114301