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2543630471141 = 5899034311947
BaseRepresentation
bin100101000000111100001…
…100001100111111100101
3100000011112222111010212012
4211000330030030333211
5313133323400034031
65224305552404005
7351525351160244
oct45007414147745
910004488433765
102543630471141
118a08250a7aa1
12350b80846605
13155b2b953076
148b1804c295b
15462741c7b2b
hex2503c30cfe5

2543630471141 has 4 divisors (see below), whose sum is σ = 2543635372992. Its totient is φ = 2543625569292.

The previous prime is 2543630471089. The next prime is 2543630471243. The reversal of 2543630471141 is 1411740363452.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2543630471141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2543630471341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1566071 + ... + 2745876.

It is an arithmetic number, because the mean of its divisors is an integer number (635908843248).

Almost surely, 22543630471141 is an apocalyptic number.

It is an amenable number.

2543630471141 is a deficient number, since it is larger than the sum of its proper divisors (4901851).

2543630471141 is an equidigital number, since it uses as much as digits as its factorization.

2543630471141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4901850.

The product of its (nonzero) digits is 241920, while the sum is 41.

The spelling of 2543630471141 in words is "two trillion, five hundred forty-three billion, six hundred thirty million, four hundred seventy-one thousand, one hundred forty-one".

Divisors: 1 589903 4311947 2543630471141