Base | Representation |
---|---|
bin | 100101000000111100001… |
… | …100001100111111100101 |
3 | 100000011112222111010212012 |
4 | 211000330030030333211 |
5 | 313133323400034031 |
6 | 5224305552404005 |
7 | 351525351160244 |
oct | 45007414147745 |
9 | 10004488433765 |
10 | 2543630471141 |
11 | 8a08250a7aa1 |
12 | 350b80846605 |
13 | 155b2b953076 |
14 | 8b1804c295b |
15 | 462741c7b2b |
hex | 2503c30cfe5 |
2543630471141 has 4 divisors (see below), whose sum is σ = 2543635372992. Its totient is φ = 2543625569292.
The previous prime is 2543630471089. The next prime is 2543630471243. The reversal of 2543630471141 is 1411740363452.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2543630471141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2543630471341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1566071 + ... + 2745876.
It is an arithmetic number, because the mean of its divisors is an integer number (635908843248).
Almost surely, 22543630471141 is an apocalyptic number.
It is an amenable number.
2543630471141 is a deficient number, since it is larger than the sum of its proper divisors (4901851).
2543630471141 is an equidigital number, since it uses as much as digits as its factorization.
2543630471141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4901850.
The product of its (nonzero) digits is 241920, while the sum is 41.
The spelling of 2543630471141 in words is "two trillion, five hundred forty-three billion, six hundred thirty million, four hundred seventy-one thousand, one hundred forty-one".
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