Base | Representation |
---|---|
bin | 111001110110000100010011… |
… | …111111010100111110010111 |
3 | 1020100202210112110102022200012 |
4 | 321312010103333110332113 |
5 | 231321124131100241210 |
6 | 2301023351222110435 |
7 | 104405043403466021 |
oct | 7166042377247627 |
9 | 1210683473368605 |
10 | 254404133212055 |
11 | 74074206994832 |
12 | 2464928557b41b |
13 | abc528c50bb08 |
14 | 46b732363d011 |
15 | 1e6297e38d305 |
hex | e76113fd4f97 |
254404133212055 has 8 divisors (see below), whose sum is σ = 305288123451072. Its totient is φ = 203521197505248.
The previous prime is 254404133212051. The next prime is 254404133212121. The reversal of 254404133212055 is 550212331404452.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 254404133212055 - 22 = 254404133212051 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (254404133212051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 263102207 + ... + 264067376.
It is an arithmetic number, because the mean of its divisors is an integer number (38161015431384).
Almost surely, 2254404133212055 is an apocalyptic number.
254404133212055 is a deficient number, since it is larger than the sum of its proper divisors (50883990239017).
254404133212055 is an equidigital number, since it uses as much as digits as its factorization.
254404133212055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 527266105.
The product of its (nonzero) digits is 576000, while the sum is 41.
The spelling of 254404133212055 in words is "two hundred fifty-four trillion, four hundred four billion, one hundred thirty-three million, two hundred twelve thousand, fifty-five".
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