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2545055313041 = 3201537949497
BaseRepresentation
bin100101000010010001000…
…111100010110010010001
3100000022020021120121111102
4211002101013202302101
5313144233130004131
65225103211554145
7351605562136253
oct45022107426221
910008207517442
102545055313041
118a139641388a
123512b9a5b955
13155cc7bbba97
148b27781dcd3
15463093281cb
hex250911e2c91

2545055313041 has 4 divisors (see below), whose sum is σ = 2545063582692. Its totient is φ = 2545047043392.

The previous prime is 2545055313013. The next prime is 2545055313049. The reversal of 2545055313041 is 1403135505452.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 55589850625 + 2489465462416 = 235775^2 + 1577804^2 .

It is a cyclic number.

It is not a de Polignac number, because 2545055313041 - 230 = 2543981571217 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2545055312986 and 2545055313004.

It is not an unprimeable number, because it can be changed into a prime (2545055313049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3654596 + ... + 4294901.

It is an arithmetic number, because the mean of its divisors is an integer number (636265895673).

Almost surely, 22545055313041 is an apocalyptic number.

It is an amenable number.

2545055313041 is a deficient number, since it is larger than the sum of its proper divisors (8269651).

2545055313041 is an equidigital number, since it uses as much as digits as its factorization.

2545055313041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8269650.

The product of its (nonzero) digits is 180000, while the sum is 38.

The spelling of 2545055313041 in words is "two trillion, five hundred forty-five billion, fifty-five million, three hundred thirteen thousand, forty-one".

Divisors: 1 320153 7949497 2545055313041