254908051 has 4 divisors (see below), whose sum is σ = 255427704. Its totient is φ = 254388400.

The previous prime is 254908037. The next prime is 254908063. The reversal of 254908051 is 150809452.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 254908051 - 2⁵ = 254908019 is a prime.

It is a super-3 number, since 3×254908051³ (a number of 26 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 254907998 and 254908016.

It is not an unprimeable number, because it can be changed into a prime (254908021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 259090 + ... + 260071.

It is an arithmetic number, because the mean of its divisors is an integer number (63856926).

Almost surely, 2^254908051 is an apocalyptic number.

254908051 is a deficient number, since it is larger than the sum of its proper divisors (519653).

254908051 is an equidigital number, since it uses as much as digits as its factorization.

254908051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 519652.

The product of its (nonzero) digits is 14400, while the sum is 34.

The square root of 254908051 is about 15965.8401282238. The cubic root of 254908051 is about 634.0563419562.

The spelling of 254908051 in words is "two hundred fifty-four million, nine hundred eight thousand, fifty-one".