Base | Representation |
---|---|
bin | 111001111110111011100100… |
… | …011001001010011000110111 |
3 | 1020102221000200202201202122011 |
4 | 321332323210121022120313 |
5 | 231411114033312042403 |
6 | 2302211242254345051 |
7 | 104500045215163426 |
oct | 7176734431123067 |
9 | 1212830622652564 |
10 | 255013220034103 |
11 | 7428955458a213 |
12 | 2472732b4bb187 |
13 | ac3a8498c7bab |
14 | 46d89c46592bd |
15 | 1e7372bd37a6d |
hex | e7eee464a637 |
255013220034103 has 4 divisors (see below), whose sum is σ = 259193764624888. Its totient is φ = 250832675443320.
The previous prime is 255013220034077. The next prime is 255013220034143. The reversal of 255013220034103 is 301430022310552.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-255013220034103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255013220034143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2090272295301 + ... + 2090272295422.
It is an arithmetic number, because the mean of its divisors is an integer number (64798441156222).
Almost surely, 2255013220034103 is an apocalyptic number.
255013220034103 is a deficient number, since it is larger than the sum of its proper divisors (4180544590785).
255013220034103 is an equidigital number, since it uses as much as digits as its factorization.
255013220034103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4180544590784.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 255013220034103 its reverse (301430022310552), we get a palindrome (556443242344655).
The spelling of 255013220034103 in words is "two hundred fifty-five trillion, thirteen billion, two hundred twenty million, thirty-four thousand, one hundred three".
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