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255013220034103 = 614180544590723
BaseRepresentation
bin111001111110111011100100…
…011001001010011000110111
31020102221000200202201202122011
4321332323210121022120313
5231411114033312042403
62302211242254345051
7104500045215163426
oct7176734431123067
91212830622652564
10255013220034103
117428955458a213
122472732b4bb187
13ac3a8498c7bab
1446d89c46592bd
151e7372bd37a6d
hexe7eee464a637

255013220034103 has 4 divisors (see below), whose sum is σ = 259193764624888. Its totient is φ = 250832675443320.

The previous prime is 255013220034077. The next prime is 255013220034143. The reversal of 255013220034103 is 301430022310552.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-255013220034103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (255013220034143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2090272295301 + ... + 2090272295422.

It is an arithmetic number, because the mean of its divisors is an integer number (64798441156222).

Almost surely, 2255013220034103 is an apocalyptic number.

255013220034103 is a deficient number, since it is larger than the sum of its proper divisors (4180544590785).

255013220034103 is an equidigital number, since it uses as much as digits as its factorization.

255013220034103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4180544590784.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 255013220034103 its reverse (301430022310552), we get a palindrome (556443242344655).

The spelling of 255013220034103 in words is "two hundred fifty-five trillion, thirteen billion, two hundred twenty million, thirty-four thousand, one hundred three".

Divisors: 1 61 4180544590723 255013220034103