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2550213103 = 3218379241
BaseRepresentation
bin1001100000000001…
…0010100111101111
320120201200020201011
42120000102213233
520210323304403
61101015530051
7120124311424
oct23000224757
96521606634
102550213103
11109958a939
125b2089927
13318460849
141a29a1d4b
15edd48a6d
hex980129ef

2550213103 has 4 divisors (see below), whose sum is σ = 2550324528. Its totient is φ = 2550101680.

The previous prime is 2550213013. The next prime is 2550213119. The reversal of 2550213103 is 3013120552.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 2550213103 - 29 = 2550212591 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2550213143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7438 + ... + 71803.

It is an arithmetic number, because the mean of its divisors is an integer number (637581132).

Almost surely, 22550213103 is an apocalyptic number.

2550213103 is a deficient number, since it is larger than the sum of its proper divisors (111425).

2550213103 is an equidigital number, since it uses as much as digits as its factorization.

2550213103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 111424.

The product of its (nonzero) digits is 900, while the sum is 22.

The square root of 2550213103 is about 50499.6346818470. The cubic root of 2550213103 is about 1366.2352645981.

Adding to 2550213103 its reverse (3013120552), we get a palindrome (5563333655).

The spelling of 2550213103 in words is "two billion, five hundred fifty million, two hundred thirteen thousand, one hundred three".

Divisors: 1 32183 79241 2550213103