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255030341 = 673806423
BaseRepresentation
bin11110011001101…
…11010001000101
3122202212212212012
433030313101011
51010241432331
641150104005
76214502456
oct1714672105
9582785765
10255030341
11120a5a085
12714ab005
1340ab4237
1425c2912d
15175c982b
hexf337445

255030341 has 4 divisors (see below), whose sum is σ = 258836832. Its totient is φ = 251223852.

The previous prime is 255030323. The next prime is 255030343. The reversal of 255030341 is 143030552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 255030341 - 210 = 255029317 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (255030343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1903145 + ... + 1903278.

It is an arithmetic number, because the mean of its divisors is an integer number (64709208).

Almost surely, 2255030341 is an apocalyptic number.

It is an amenable number.

255030341 is a deficient number, since it is larger than the sum of its proper divisors (3806491).

255030341 is an equidigital number, since it uses as much as digits as its factorization.

255030341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3806490.

The product of its (nonzero) digits is 1800, while the sum is 23.

The square root of 255030341 is about 15969.6694079746. The cubic root of 255030341 is about 634.1577201506.

Adding to 255030341 its reverse (143030552), we get a palindrome (398060893).

The spelling of 255030341 in words is "two hundred fifty-five million, thirty thousand, three hundred forty-one".

Divisors: 1 67 3806423 255030341