Base | Representation |
---|---|
bin | 111001111111001100010000… |
… | …100001100110101110011101 |
3 | 1020102222201221122220022020220 |
4 | 321333030100201212232131 |
5 | 231411412233410022023 |
6 | 2302223404412231553 |
7 | 104501251255066440 |
oct | 7177142041465635 |
9 | 1212881848808226 |
10 | 255031140314013 |
11 | 742961100717a8 |
12 | 2472a8b0a6b5b9 |
13 | ac3c44446560b |
14 | 46d9804653657 |
15 | 1e73e2a1e53e3 |
hex | e7f310866b9d |
255031140314013 has 16 divisors (see below), whose sum is σ = 389701384335360. Its totient is φ = 145326141233136.
The previous prime is 255031140313969. The next prime is 255031140314029. The reversal of 255031140314013 is 310413041130552.
It is not a de Polignac number, because 255031140314013 - 217 = 255031140182941 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255031140314053) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16914115045 + ... + 16914130122.
It is an arithmetic number, because the mean of its divisors is an integer number (24356336520960).
Almost surely, 2255031140314013 is an apocalyptic number.
It is an amenable number.
255031140314013 is a deficient number, since it is larger than the sum of its proper divisors (134670244021347).
255031140314013 is a wasteful number, since it uses less digits than its factorization.
255031140314013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33828245536.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 255031140314013 its reverse (310413041130552), we get a palindrome (565444181444565).
The spelling of 255031140314013 in words is "two hundred fifty-five trillion, thirty-one billion, one hundred forty million, three hundred fourteen thousand, thirteen".
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