Base | Representation |
---|---|
bin | 111001111111001110010011… |
… | …000010101011011100000001 |
3 | 1020102222221121021020000010002 |
4 | 321333032103002223130001 |
5 | 231411431224441202040 |
6 | 2302224405553245345 |
7 | 104501356444232243 |
oct | 7177162302533401 |
9 | 1212887537200102 |
10 | 255033330022145 |
11 | 74297034101944 |
12 | 2472b202263855 |
13 | ac3c7030025bc |
14 | 46d99713b2093 |
15 | 1e7400757ca15 |
hex | e7f3930ab701 |
255033330022145 has 16 divisors (see below), whose sum is σ = 306389568763200. Its totient is φ = 203793620030784.
The previous prime is 255033330022091. The next prime is 255033330022169. The reversal of 255033330022145 is 541220033330552.
It is a cyclic number.
It is not a de Polignac number, because 255033330022145 - 214 = 255033330005761 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 255033330022099 and 255033330022108.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 597352442 + ... + 597779228.
It is an arithmetic number, because the mean of its divisors is an integer number (19149348047700).
Almost surely, 2255033330022145 is an apocalyptic number.
It is an amenable number.
255033330022145 is a deficient number, since it is larger than the sum of its proper divisors (51356238741055).
255033330022145 is a wasteful number, since it uses less digits than its factorization.
255033330022145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 563024.
The product of its (nonzero) digits is 324000, while the sum is 38.
Adding to 255033330022145 its reverse (541220033330552), we get a palindrome (796253363352697).
The spelling of 255033330022145 in words is "two hundred fifty-five trillion, thirty-three billion, three hundred thirty million, twenty-two thousand, one hundred forty-five".
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