Base | Representation |
---|---|
bin | 1110110110001011110… |
… | …1011010010111011101 |
3 | 220101100210122222220112 |
4 | 3231202331122113131 |
5 | 13134332203231123 |
6 | 313101404255405 |
7 | 24266464405334 |
oct | 3554275322735 |
9 | 811323588815 |
10 | 255063336413 |
11 | 991986708a6 |
12 | 41524241565 |
13 | 1b08b095242 |
14 | c4b907cd1b |
15 | 697c5d1d78 |
hex | 3b62f5a5dd |
255063336413 has 8 divisors (see below), whose sum is σ = 269601784320. Its totient is φ = 240636294720.
The previous prime is 255063336397. The next prime is 255063336433. The reversal of 255063336413 is 314633360552.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 255063336413 - 24 = 255063336397 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255063336433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27846845 + ... + 27856002.
It is an arithmetic number, because the mean of its divisors is an integer number (33700223040).
Almost surely, 2255063336413 is an apocalyptic number.
It is an amenable number.
255063336413 is a deficient number, since it is larger than the sum of its proper divisors (14538447907).
255063336413 is a wasteful number, since it uses less digits than its factorization.
255063336413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55703107.
The product of its (nonzero) digits is 583200, while the sum is 41.
Adding to 255063336413 its reverse (314633360552), we get a palindrome (569696696965).
The spelling of 255063336413 in words is "two hundred fifty-five billion, sixty-three million, three hundred thirty-six thousand, four hundred thirteen".
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