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255104103 = 385034701
BaseRepresentation
bin11110011010010…
…01010001100111
3122210000122001010
433031021101213
51010301312403
641151433303
76215230512
oct1715112147
9583018033
10255104103
11120aaa541
1271525833
1340b0b997
1425c47d79
15175e1603
hexf349467

255104103 has 4 divisors (see below), whose sum is σ = 340138808. Its totient is φ = 170069400.

The previous prime is 255104099. The next prime is 255104107. The reversal of 255104103 is 301401552.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (255104099) and next prime (255104107).

It is not a de Polignac number, because 255104103 - 22 = 255104099 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 255104103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (255104107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42517348 + ... + 42517353.

It is an arithmetic number, because the mean of its divisors is an integer number (85034702).

Almost surely, 2255104103 is an apocalyptic number.

255104103 is a deficient number, since it is larger than the sum of its proper divisors (85034705).

255104103 is an equidigital number, since it uses as much as digits as its factorization.

255104103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 85034704.

The product of its (nonzero) digits is 600, while the sum is 21.

The square root of 255104103 is about 15971.9786814283. The cubic root of 255104103 is about 634.2188530503.

Adding to 255104103 its reverse (301401552), we get a palindrome (556505655).

The spelling of 255104103 in words is "two hundred fifty-five million, one hundred four thousand, one hundred three".

Divisors: 1 3 85034701 255104103