255135350403151 has 8 divisors (see below), whose sum is σ = 258730654093344. Its totient is φ = 251540098047840.

The previous prime is 255135350403127. The next prime is 255135350403187. The reversal of 255135350403151 is 151304053531552.

255135350403151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 255135350403151 - 2¹¹ = 255135350401103 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 255135350403098 and 255135350403107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (255135350443151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2768416 + ... + 22758181.

It is an arithmetic number, because the mean of its divisors is an integer number (32341331761668).

Almost surely, 2^{255135350403151} is an apocalyptic number.

255135350403151 is a deficient number, since it is larger than the sum of its proper divisors (3595303690193).

255135350403151 is a wasteful number, since it uses less digits than its factorization.

255135350403151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25667441.

The product of its (nonzero) digits is 675000, while the sum is 43.

The spelling of 255135350403151 in words is "two hundred fifty-five trillion, one hundred thirty-five billion, three hundred fifty million, four hundred three thousand, one hundred fifty-one".