Base | Representation |
---|---|
bin | 1110110110011101011… |
… | …0110100011000111111 |
3 | 220101112221110212000212 |
4 | 3231213112310120333 |
5 | 13140010044333341 |
6 | 313113001343035 |
7 | 24301351420433 |
oct | 3554726643077 |
9 | 811487425025 |
10 | 255137105471 |
11 | 99226276666 |
12 | 41544a97a7b |
13 | 1b0a0453481 |
14 | c4c4ba29c3 |
15 | 6983d045eb |
hex | 3b675b463f |
255137105471 has 8 divisors (see below), whose sum is σ = 275115750000. Its totient is φ = 235813498560.
The previous prime is 255137105429. The next prime is 255137105477. The reversal of 255137105471 is 174501731552.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 255137105471 - 218 = 255136843327 is a prime.
It is a super-3 number, since 3×2551371054713 (a number of 35 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (41).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255137105477) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 163758596 + ... + 163760153.
It is an arithmetic number, because the mean of its divisors is an integer number (34389468750).
Almost surely, 2255137105471 is an apocalyptic number.
255137105471 is a deficient number, since it is larger than the sum of its proper divisors (19978644529).
255137105471 is a wasteful number, since it uses less digits than its factorization.
255137105471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 327518809.
The product of its (nonzero) digits is 147000, while the sum is 41.
The spelling of 255137105471 in words is "two hundred fifty-five billion, one hundred thirty-seven million, one hundred five thousand, four hundred seventy-one".
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