Search a number
-
+
2551412433 = 35711489441
BaseRepresentation
bin1001100000010011…
…0111011011010001
320120210221011212210
42120010313123101
520211130144213
61101101342333
7120140435133
oct23004673321
96523834783
102551412433
11109a229a19
125b25679a9
133187906cb
141a2bd5053
15eded40c3
hex981376d1

2551412433 has 8 divisors (see below), whose sum is σ = 3407843296. Its totient is φ = 1697961600.

The previous prime is 2551412419. The next prime is 2551412453. The reversal of 2551412433 is 3342141552.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2551412433 - 25 = 2551412401 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2551412433.

It is not an unprimeable number, because it can be changed into a prime (2551412453) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 743008 + ... + 746433.

It is an arithmetic number, because the mean of its divisors is an integer number (425980412).

Almost surely, 22551412433 is an apocalyptic number.

It is an amenable number.

2551412433 is a deficient number, since it is larger than the sum of its proper divisors (856430863).

2551412433 is a wasteful number, since it uses less digits than its factorization.

2551412433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1490015.

The product of its digits is 14400, while the sum is 30.

The square root of 2551412433 is about 50511.5079264122. The cubic root of 2551412433 is about 1366.4494048909.

Adding to 2551412433 its reverse (3342141552), we get a palindrome (5893553985).

The spelling of 2551412433 in words is "two billion, five hundred fifty-one million, four hundred twelve thousand, four hundred thirty-three".

Divisors: 1 3 571 1713 1489441 4468323 850470811 2551412433