2551434133 has 4 divisors (see below), whose sum is σ = 2685720160. Its totient is φ = 2417148108.

The previous prime is 2551434107. The next prime is 2551434139. The reversal of 2551434133 is 3314341552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2551434133 - 2²¹ = 2549336981 is a prime.

It is a super-2 number, since 2×2551434133² = 13019632270074923378, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2551434095 and 2551434104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2551434139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67142985 + ... + 67143022.

It is an arithmetic number, because the mean of its divisors is an integer number (671430040).

Almost surely, 2^2551434133 is an apocalyptic number.

It is an amenable number.

2551434133 is a deficient number, since it is larger than the sum of its proper divisors (134286027).

2551434133 is a wasteful number, since it uses less digits than its factorization.

2551434133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 134286026.

The product of its digits is 21600, while the sum is 31.

The square root of 2551434133 is about 50511.7227284915. The cubic root of 2551434133 is about 1366.4532788063.

Adding to 2551434133 its reverse (3314341552), we get a palindrome (5865775685).

The spelling of 2551434133 in words is "two billion, five hundred fifty-one million, four hundred thirty-four thousand, one hundred thirty-three".