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255234125343 = 31714933587857
BaseRepresentation
bin1110110110110100100…
…0111010111000011111
3220101210201000222021110
43231231020322320133
513140204414002333
6313130345033103
724303640161261
oct3555510727037
9811721028243
10255234125343
119927601207a
1241571485793
131b0b7592692
14c4d3a19b31
15698c5bb063
hex3b6d23ae1f

255234125343 has 16 divisors (see below), whose sum is σ = 362748866400. Its totient is φ = 159072086016.

The previous prime is 255234125243. The next prime is 255234125353. The reversal of 255234125343 is 343521432552.

It is not a de Polignac number, because 255234125343 - 28 = 255234125087 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (255234125353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16786330 + ... + 16801527.

It is an arithmetic number, because the mean of its divisors is an integer number (22671804150).

Almost surely, 2255234125343 is an apocalyptic number.

255234125343 is a deficient number, since it is larger than the sum of its proper divisors (107514741057).

255234125343 is a wasteful number, since it uses less digits than its factorization.

255234125343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33588026.

The product of its digits is 432000, while the sum is 39.

Adding to 255234125343 its reverse (343521432552), we get a palindrome (598755557895).

The spelling of 255234125343 in words is "two hundred fifty-five billion, two hundred thirty-four million, one hundred twenty-five thousand, three hundred forty-three".

Divisors: 1 3 17 51 149 447 2533 7599 33587857 100763571 570993569 1712980707 5004590693 15013772079 85078041781 255234125343