Base | Representation |
---|---|
bin | 1110110110111000010… |
… | …1011110101001110111 |
3 | 220101211210220111220100 |
4 | 3231232011132221313 |
5 | 13140223000004003 |
6 | 313132113205143 |
7 | 24304222130451 |
oct | 3555605365167 |
9 | 811753814810 |
10 | 255250000503 |
11 | 99283a75343 |
12 | 415768607b3 |
13 | 1b0ba960474 |
14 | c4d5b8d2d1 |
15 | 698dba4ba3 |
hex | 3b6e15ea77 |
255250000503 has 12 divisors (see below), whose sum is σ = 368701716240. Its totient is φ = 170163311136.
The previous prime is 255250000501. The next prime is 255250000541. The reversal of 255250000503 is 305000052552.
It is not a de Polignac number, because 255250000503 - 21 = 255250000501 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255250000501) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 256078 + ... + 758996.
It is an arithmetic number, because the mean of its divisors is an integer number (30725143020).
Almost surely, 2255250000503 is an apocalyptic number.
255250000503 is a deficient number, since it is larger than the sum of its proper divisors (113451715737).
255250000503 is a wasteful number, since it uses less digits than its factorization.
255250000503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 559318 (or 559315 counting only the distinct ones).
The product of its (nonzero) digits is 7500, while the sum is 27.
The spelling of 255250000503 in words is "two hundred fifty-five billion, two hundred fifty million, five hundred three", and thus it is an aban number.
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