Base | Representation |
---|---|
bin | 1011100110111000000111… |
… | …10111100111001001100111 |
3 | 10100101011122000020011110211 |
4 | 11303130003313213021213 |
5 | 11321200303210100210 |
6 | 130142014301200251 |
7 | 5243060446226335 |
oct | 563340367471147 |
9 | 110334560204424 |
10 | 25525055550055 |
11 | 815112a46a656 |
12 | 2a42b15560087 |
13 | 11320053ab919 |
14 | 6435c2710b55 |
15 | 2e3e72bd238a |
hex | 173703de7267 |
25525055550055 has 8 divisors (see below), whose sum is σ = 30630255556032. Its totient is φ = 20419918509408.
The previous prime is 25525055550037. The next prime is 25525055550083. The reversal of 25525055550055 is 55005555052552.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 25525055550055 - 211 = 25525055548007 is a prime.
It is a super-2 number, since 2×255250555500552 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 25525055549990 and 25525055550008.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14844847 + ... + 16474816.
It is an arithmetic number, because the mean of its divisors is an integer number (3828781944504).
Almost surely, 225525055550055 is an apocalyptic number.
25525055550055 is a deficient number, since it is larger than the sum of its proper divisors (5105200005977).
25525055550055 is a wasteful number, since it uses less digits than its factorization.
25525055550055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31482665.
The product of its (nonzero) digits is 7812500, while the sum is 49.
The spelling of 25525055550055 in words is "twenty-five trillion, five hundred twenty-five billion, fifty-five million, five hundred fifty thousand, fifty-five".
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