Base | Representation |
---|---|
bin | 1110110110111000101… |
… | …0001101110010010111 |
3 | 220101211220020121002201 |
4 | 3231232022031302113 |
5 | 13140223304222020 |
6 | 313132155545331 |
7 | 24304235521411 |
oct | 3555612156227 |
9 | 811756217081 |
10 | 255251242135 |
11 | 9928474318a |
12 | 4157715b247 |
13 | 1b0baca6666 |
14 | c4d5dd39b1 |
15 | 698dd4ca0a |
hex | 3b6e28dc97 |
255251242135 has 16 divisors (see below), whose sum is σ = 309203294400. Its totient is φ = 202267570176.
The previous prime is 255251242111. The next prime is 255251242163. The reversal of 255251242135 is 531242152552.
It is a cyclic number.
It is not a de Polignac number, because 255251242135 - 219 = 255250717847 is a prime.
It is a super-2 number, since 2×2552512421352 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 255251242094 and 255251242103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1816326 + ... + 1951804.
It is an arithmetic number, because the mean of its divisors is an integer number (19325205900).
Almost surely, 2255251242135 is an apocalyptic number.
255251242135 is a deficient number, since it is larger than the sum of its proper divisors (53952052265).
255251242135 is a wasteful number, since it uses less digits than its factorization.
255251242135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 139050.
The product of its digits is 120000, while the sum is 37.
Adding to 255251242135 its reverse (531242152552), we get a palindrome (786493394687).
The spelling of 255251242135 in words is "two hundred fifty-five billion, two hundred fifty-one million, two hundred forty-two thousand, one hundred thirty-five".
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