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2553000551 = 17150176503
BaseRepresentation
bin1001100000101011…
…1011001001100111
320120220220212100222
42120022323021213
520212032004201
61101155354555
7120160101203
oct23012731147
96526825328
102553000551
1110a0114112
125b2bb2a5b
13318bc851a
141a30c9b03
15ee1e991b
hex982bb267

2553000551 has 4 divisors (see below), whose sum is σ = 2703177072. Its totient is φ = 2402824032.

The previous prime is 2553000509. The next prime is 2553000563. The reversal of 2553000551 is 1550003552.

2553000551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2553000551 - 214 = 2552984167 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2553000551.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2553050551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75088235 + ... + 75088268.

It is an arithmetic number, because the mean of its divisors is an integer number (675794268).

Almost surely, 22553000551 is an apocalyptic number.

2553000551 is a deficient number, since it is larger than the sum of its proper divisors (150176521).

2553000551 is a wasteful number, since it uses less digits than its factorization.

2553000551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 150176520.

The product of its (nonzero) digits is 3750, while the sum is 26.

The square root of 2553000551 is about 50527.2258391454. The cubic root of 2553000551 is about 1366.7328600169.

The spelling of 2553000551 in words is "two billion, five hundred fifty-three million, five hundred fifty-one", and thus it is an aban number.

Divisors: 1 17 150176503 2553000551