Base | Representation |
---|---|
bin | 111010000011000110111110… |
… | …110000110001111011011111 |
3 | 1020110221110211110020112020001 |
4 | 322003012332300301323133 |
5 | 231430320104440444444 |
6 | 2302551210134235131 |
7 | 104526561464316001 |
oct | 7203067660617337 |
9 | 1213843743215201 |
10 | 255300351499999 |
11 | 7438a2a8834363 |
12 | 24772b031b5aa7 |
13 | ac5b948664880 |
14 | 4708862694371 |
15 | 1e7ae348b28d4 |
hex | e831bec31edf |
255300351499999 has 16 divisors (see below), whose sum is σ = 274971305236320. Its totient is φ = 235634037690240.
The previous prime is 255300351499969. The next prime is 255300351500017. The reversal of 255300351499999 is 999994153003552.
It is a cyclic number.
It is not a de Polignac number, because 255300351499999 - 25 = 255300351499967 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255300351499969) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7031693404 + ... + 7031729710.
It is an arithmetic number, because the mean of its divisors is an integer number (17185706577270).
Almost surely, 2255300351499999 is an apocalyptic number.
255300351499999 is a deficient number, since it is larger than the sum of its proper divisors (19670953736321).
255300351499999 is a wasteful number, since it uses less digits than its factorization.
255300351499999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85290.
The product of its (nonzero) digits is 531441000, while the sum is 73.
The spelling of 255300351499999 in words is "two hundred fifty-five trillion, three hundred billion, three hundred fifty-one million, four hundred ninety-nine thousand, nine hundred ninety-nine".
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