Base | Representation |
---|---|
bin | 100101001001110100100… |
… | …011111011000000011101 |
3 | 100001002011112112200211212 |
4 | 211021310203323000131 |
5 | 313312341013210423 |
6 | 5232524111154205 |
7 | 352313560115264 |
oct | 45116443730035 |
9 | 10032145480755 |
10 | 2553166147613 |
11 | 8a4878802954 |
12 | 3529a2215965 |
13 | 1569bb39a093 |
14 | 8b806ad95db |
15 | 46631418578 |
hex | 252748fb01d |
2553166147613 has 4 divisors (see below), whose sum is σ = 2553336181020. Its totient is φ = 2552996114208.
The previous prime is 2553166147573. The next prime is 2553166147639. The reversal of 2553166147613 is 3167416613552.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 647957381764 + 1905208765849 = 804958^2 + 1380293^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2553166147613 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2553166147663) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84994178 + ... + 85024211.
It is an arithmetic number, because the mean of its divisors is an integer number (638334045255).
Almost surely, 22553166147613 is an apocalyptic number.
It is an amenable number.
2553166147613 is a deficient number, since it is larger than the sum of its proper divisors (170033407).
2553166147613 is a wasteful number, since it uses less digits than its factorization.
2553166147613 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 170033406.
The product of its digits is 2721600, while the sum is 50.
The spelling of 2553166147613 in words is "two trillion, five hundred fifty-three billion, one hundred sixty-six million, one hundred forty-seven thousand, six hundred thirteen".
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