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2553251403 = 31750063753
BaseRepresentation
bin1001100000101111…
…1000011001001011
320120221101121110210
42120023320121023
520212113021103
61101205012203
7120162164433
oct23013703113
96527347423
102553251403
1110a027562a
125b30b4063
13318c85761
141a31532c3
15ee248e03
hex982f864b

2553251403 has 8 divisors (see below), whose sum is σ = 3604590288. Its totient is φ = 1602040064.

The previous prime is 2553251383. The next prime is 2553251443. The reversal of 2553251403 is 3041523552.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2553251403 - 214 = 2553235019 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2553251443) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25031826 + ... + 25031927.

It is an arithmetic number, because the mean of its divisors is an integer number (450573786).

Almost surely, 22553251403 is an apocalyptic number.

2553251403 is a deficient number, since it is larger than the sum of its proper divisors (1051338885).

2553251403 is a wasteful number, since it uses less digits than its factorization.

2553251403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50063773.

The product of its (nonzero) digits is 18000, while the sum is 30.

The square root of 2553251403 is about 50529.7081230438. The cubic root of 2553251403 is about 1366.7776225667. Note that the first 3 decimals are identical.

Adding to 2553251403 its reverse (3041523552), we get a palindrome (5594774955).

The spelling of 2553251403 in words is "two billion, five hundred fifty-three million, two hundred fifty-one thousand, four hundred three".

Divisors: 1 3 17 51 50063753 150191259 851083801 2553251403