Base | Representation |
---|---|
bin | 111010000011110110001110… |
… | …000101010011111110011111 |
3 | 1020111010022202102100010212110 |
4 | 322003312032011103332133 |
5 | 231432133000022000203 |
6 | 2303030355242205103 |
7 | 104533335445025211 |
oct | 7203661605237637 |
9 | 1214108672303773 |
10 | 255351074406303 |
11 | 743a9867571637 |
12 | 247808ba1b3793 |
13 | ac63670103bb5 |
14 | 470b0b50025b1 |
15 | 1e7c402951d03 |
hex | e83d8e153f9f |
255351074406303 has 16 divisors (see below), whose sum is σ = 355278384898560. Its totient is φ = 162829211961504.
The previous prime is 255351074406299. The next prime is 255351074406359. The reversal of 255351074406303 is 303604470153552.
It is not a de Polignac number, because 255351074406303 - 22 = 255351074406299 is a prime.
It is a super-2 number, since 2×2553510744063032 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255351074401303) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34777243 + ... + 41474796.
It is an arithmetic number, because the mean of its divisors is an integer number (22204899056160).
Almost surely, 2255351074406303 is an apocalyptic number.
255351074406303 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
255351074406303 is a deficient number, since it is larger than the sum of its proper divisors (99927310492257).
255351074406303 is a wasteful number, since it uses less digits than its factorization.
255351074406303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76300598.
The product of its (nonzero) digits is 4536000, while the sum is 48.
The spelling of 255351074406303 in words is "two hundred fifty-five trillion, three hundred fifty-one billion, seventy-four million, four hundred six thousand, three hundred three".
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