Base | Representation |
---|---|
bin | 111010000100101110011001… |
… | …110001001110110111000101 |
3 | 1020111100002110121121101120111 |
4 | 322010232121301032313011 |
5 | 231434130021400324310 |
6 | 2303114213301233021 |
7 | 104540602410144304 |
oct | 7204563161166705 |
9 | 1214302417541514 |
10 | 255411400011205 |
11 | 74422403821459 |
12 | 24790535102771 |
13 | ac692651554b9 |
14 | 470dd98c1243b |
15 | 1e7dc83a7028a |
hex | e84b99c4edc5 |
255411400011205 has 16 divisors (see below), whose sum is σ = 308910209034240. Its totient is φ = 202718133922752.
The previous prime is 255411400011151. The next prime is 255411400011259. The reversal of 255411400011205 is 502110004114552.
It is an interprime number because it is at equal distance from previous prime (255411400011151) and next prime (255411400011259).
It is a cyclic number.
It is not a de Polignac number, because 255411400011205 - 219 = 255411399486917 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 60905022 + ... + 64963408.
It is an arithmetic number, because the mean of its divisors is an integer number (19306888064640).
Almost surely, 2255411400011205 is an apocalyptic number.
It is an amenable number.
255411400011205 is a deficient number, since it is larger than the sum of its proper divisors (53498809023035).
255411400011205 is a wasteful number, since it uses less digits than its factorization.
255411400011205 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4157628.
The product of its (nonzero) digits is 8000, while the sum is 31.
Adding to 255411400011205 its reverse (502110004114552), we get a palindrome (757521404125757).
The spelling of 255411400011205 in words is "two hundred fifty-five trillion, four hundred eleven billion, four hundred million, eleven thousand, two hundred five".
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