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2554120032013 = 11283781844459
BaseRepresentation
bin100101001010101101011…
…010101100111100001101
3100001011122000110001020201
4211022231122230330031
5313321314212011023
65233202504213501
7352346322030334
oct45125532547415
910034560401221
102554120032013
118a5218199370
1235300976a291
13156b10babc14
148b897680d1b
154668a03abad
hex252ad6acf0d

2554120032013 has 8 divisors (see below), whose sum is σ = 2787294929760. Its totient is φ = 2321108828880.

The previous prime is 2554120031993. The next prime is 2554120032031. The reversal of 2554120032013 is 3102300214552.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2554120032013 - 221 = 2554117934861 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2554120032613) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 40891023 + ... + 40953436.

It is an arithmetic number, because the mean of its divisors is an integer number (348411866220).

Almost surely, 22554120032013 is an apocalyptic number.

It is an amenable number.

2554120032013 is a deficient number, since it is larger than the sum of its proper divisors (233174897747).

2554120032013 is a wasteful number, since it uses less digits than its factorization.

2554120032013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81847307.

The product of its (nonzero) digits is 7200, while the sum is 28.

Adding to 2554120032013 its reverse (3102300214552), we get a palindrome (5656420246565).

The spelling of 2554120032013 in words is "two trillion, five hundred fifty-four billion, one hundred twenty million, thirty-two thousand, thirteen".

Divisors: 1 11 2837 31207 81844459 900289049 232192730183 2554120032013