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255412117 = 1913442743
BaseRepresentation
bin11110011100101…
…00011110010101
3122210121021120001
433032110132111
51010341141432
641202211301
76220652512
oct1716243625
9583537501
10255412117
1112119a9a4
1271653b31
1340bb8c3c
1425cc8309
15176529e7
hexf394795

255412117 has 4 divisors (see below), whose sum is σ = 268854880. Its totient is φ = 241969356.

The previous prime is 255412099. The next prime is 255412127. The reversal of 255412117 is 711214552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 255412117 - 215 = 255379349 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (255412127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6721353 + ... + 6721390.

It is an arithmetic number, because the mean of its divisors is an integer number (67213720).

Almost surely, 2255412117 is an apocalyptic number.

It is an amenable number.

255412117 is a deficient number, since it is larger than the sum of its proper divisors (13442763).

255412117 is a wasteful number, since it uses less digits than its factorization.

255412117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13442762.

The product of its digits is 2800, while the sum is 28.

The square root of 255412117 is about 15981.6180970514. The cubic root of 255412117 is about 634.4740034179.

Adding to 255412117 its reverse (711214552), we get a palindrome (966626669).

The spelling of 255412117 in words is "two hundred fifty-five million, four hundred twelve thousand, one hundred seventeen".

Divisors: 1 19 13442743 255412117