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255414403 = 475434349
BaseRepresentation
bin11110011100101…
…01000010000011
3122210121101200201
433032111002003
51010341230103
641202230031
76220662256
oct1716250203
9583541621
10255414403
111211a1692
1271655317
1340bb9caa
1425cc909d
151765351d
hexf395083

255414403 has 4 divisors (see below), whose sum is σ = 260848800. Its totient is φ = 249980008.

The previous prime is 255414331. The next prime is 255414407. The reversal of 255414403 is 304414552.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 255414403 - 217 = 255283331 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (255414407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2717128 + ... + 2717221.

It is an arithmetic number, because the mean of its divisors is an integer number (65212200).

Almost surely, 2255414403 is an apocalyptic number.

255414403 is a deficient number, since it is larger than the sum of its proper divisors (5434397).

255414403 is an equidigital number, since it uses as much as digits as its factorization.

255414403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5434396.

The product of its (nonzero) digits is 9600, while the sum is 28.

The square root of 255414403 is about 15981.6896165581. The cubic root of 255414403 is about 634.4758963107.

Adding to 255414403 its reverse (304414552), we get a palindrome (559828955).

The spelling of 255414403 in words is "two hundred fifty-five million, four hundred fourteen thousand, four hundred three".

Divisors: 1 47 5434349 255414403