Base | Representation |
---|---|
bin | 1011100111011010001000… |
… | …01010010100001010110011 |
3 | 10100102220202110211210000221 |
4 | 11303231010022110022303 |
5 | 11322000201400022201 |
6 | 130154234140353511 |
7 | 5244305064103510 |
oct | 563550412241263 |
9 | 110386673753027 |
10 | 25543314064051 |
11 | 8158949970443 |
12 | 2a46570245897 |
13 | 1133955042c64 |
14 | 6444355d2307 |
15 | 2e4690b024a1 |
hex | 173b442942b3 |
25543314064051 has 16 divisors (see below), whose sum is σ = 29297583590400. Its totient is φ = 21815361646848.
The previous prime is 25543314064013. The next prime is 25543314064097. The reversal of 25543314064051 is 15046041334552.
It is not a de Polignac number, because 25543314064051 - 27 = 25543314063923 is a prime.
It is a super-2 number, since 2×255433140640512 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 25543314063989 and 25543314064007.
It is not an unprimeable number, because it can be changed into a prime (25543314064951) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28016310 + ... + 28913668.
It is an arithmetic number, because the mean of its divisors is an integer number (1831098974400).
Almost surely, 225543314064051 is an apocalyptic number.
25543314064051 is a deficient number, since it is larger than the sum of its proper divisors (3754269526349).
25543314064051 is a wasteful number, since it uses less digits than its factorization.
25543314064051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 912018.
The product of its (nonzero) digits is 864000, while the sum is 43.
The spelling of 25543314064051 in words is "twenty-five trillion, five hundred forty-three billion, three hundred fourteen million, sixty-four thousand, fifty-one".
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