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25543314064013 is a prime number
BaseRepresentation
bin1011100111011010001000…
…01010010100001010001101
310100102220202110211202222112
411303231010022110022031
511322000201400022023
6130154234140353405
75244305064103424
oct563550412241215
9110386673752875
1025543314064013
118158949970409
122a46570245865
131133955042c35
146444355d22bb
152e4690b02478
hex173b4429428d

25543314064013 has 2 divisors, whose sum is σ = 25543314064014. Its totient is φ = 25543314064012.

The previous prime is 25543314063997. The next prime is 25543314064097. The reversal of 25543314064013 is 31046041334552.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23114585064169 + 2428728999844 = 4807763^2 + 1558438^2 .

It is a cyclic number.

It is not a de Polignac number, because 25543314064013 - 24 = 25543314063997 is a prime.

It is a super-3 number, since 3×255433140640133 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25543314064313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12771657032006 + 12771657032007.

It is an arithmetic number, because the mean of its divisors is an integer number (12771657032007).

Almost surely, 225543314064013 is an apocalyptic number.

It is an amenable number.

25543314064013 is a deficient number, since it is larger than the sum of its proper divisors (1).

25543314064013 is an equidigital number, since it uses as much as digits as its factorization.

25543314064013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 518400, while the sum is 41.

Adding to 25543314064013 its reverse (31046041334552), we get a palindrome (56589355398565).

The spelling of 25543314064013 in words is "twenty-five trillion, five hundred forty-three billion, three hundred fourteen million, sixty-four thousand, thirteen".