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2554417057 = 19134443003
BaseRepresentation
bin1001100001000001…
…0100111110100001
320121000120211110011
42120100110332201
520212412321212
61101250004521
7120205121023
oct23020247641
96530524404
102554417057
1110a09a1385
125b3576741
133192a31aa
141a3378013
15ee3c94a7
hex98414fa1

2554417057 has 4 divisors (see below), whose sum is σ = 2688860080. Its totient is φ = 2419974036.

The previous prime is 2554417051. The next prime is 2554417067. The reversal of 2554417057 is 7507144552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2554417057 - 23 = 2554417049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2554417051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67221483 + ... + 67221520.

It is an arithmetic number, because the mean of its divisors is an integer number (672215020).

Almost surely, 22554417057 is an apocalyptic number.

It is an amenable number.

2554417057 is a deficient number, since it is larger than the sum of its proper divisors (134443023).

2554417057 is a wasteful number, since it uses less digits than its factorization.

2554417057 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 134443022.

The product of its (nonzero) digits is 196000, while the sum is 40.

The square root of 2554417057 is about 50541.2411501736. The cubic root of 2554417057 is about 1366.9855858212.

The spelling of 2554417057 in words is "two billion, five hundred fifty-four million, four hundred seventeen thousand, fifty-seven".

Divisors: 1 19 134443003 2554417057