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2554417049 is a prime number
BaseRepresentation
bin1001100001000001…
…0100111110011001
320121000120211102212
42120100110332121
520212412321144
61101250004505
7120205121012
oct23020247631
96530524385
102554417049
1110a09a1378
125b3576735
133192a31a2
141a3378009
15ee3c949e
hex98414f99

2554417049 has 2 divisors, whose sum is σ = 2554417050. Its totient is φ = 2554417048.

The previous prime is 2554417043. The next prime is 2554417051. The reversal of 2554417049 is 9407144552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2496001600 + 58415449 = 49960^2 + 7643^2 .

It is a cyclic number.

It is not a de Polignac number, because 2554417049 - 28 = 2554416793 is a prime.

Together with 2554417051, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2554416997 and 2554417015.

It is not a weakly prime, because it can be changed into another prime (2554417043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1277208524 + 1277208525.

It is an arithmetic number, because the mean of its divisors is an integer number (1277208525).

Almost surely, 22554417049 is an apocalyptic number.

It is an amenable number.

2554417049 is a deficient number, since it is larger than the sum of its proper divisors (1).

2554417049 is an equidigital number, since it uses as much as digits as its factorization.

2554417049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 201600, while the sum is 41.

The square root of 2554417049 is about 50541.2410710303. The cubic root of 2554417049 is about 1366.9855843942.

The spelling of 2554417049 in words is "two billion, five hundred fifty-four million, four hundred seventeen thousand, forty-nine".