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255444314234 = 2127722157117
BaseRepresentation
bin1110110111100110101…
…0101110100001111010
3220102100100112200020012
43231321222232201322
513141122221023414
6313203254101522
724312101563004
oct3557152564172
9812310480205
10255444314234
11993737240aa
124160b94a8a2
131b11bca64c5
14c5138d1374
1569a0c8933e
hex3b79aae87a

255444314234 has 4 divisors (see below), whose sum is σ = 383166471354. Its totient is φ = 127722157116.

The previous prime is 255444314197. The next prime is 255444314263. The reversal of 255444314234 is 432413444552.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 213809136025 + 41635178209 = 462395^2 + 204047^2 .

It is a junction number, because it is equal to n+sod(n) for n = 255444314191 and 255444314200.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63861078557 + ... + 63861078560.

Almost surely, 2255444314234 is an apocalyptic number.

255444314234 is a deficient number, since it is larger than the sum of its proper divisors (127722157120).

255444314234 is a wasteful number, since it uses less digits than its factorization.

255444314234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 127722157119.

The product of its digits is 921600, while the sum is 41.

Adding to 255444314234 its reverse (432413444552), we get a palindrome (687857758786).

The spelling of 255444314234 in words is "two hundred fifty-five billion, four hundred forty-four million, three hundred fourteen thousand, two hundred thirty-four".

Divisors: 1 2 127722157117 255444314234