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25550100131 = 79323418989
BaseRepresentation
bin10111110010111001…
…111001011010100011
32102221122000120022212
4113302321321122203
5404311311201011
615423151152335
71563104160563
oct276271713243
972848016285
1025550100131
11a921402436
124b508156ab
1325424b045a
141345460da3
159e813508b
hex5f2e796a3

25550100131 has 4 divisors (see below), whose sum is σ = 25873519200. Its totient is φ = 25226681064.

The previous prime is 25550100119. The next prime is 25550100179. The reversal of 25550100131 is 13100105552.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 25550100131 - 26 = 25550100067 is a prime.

It is a super-2 number, since 2×255501001312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 25550100097 and 25550100106.

It is not an unprimeable number, because it can be changed into a prime (25550100101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 161709416 + ... + 161709573.

It is an arithmetic number, because the mean of its divisors is an integer number (6468379800).

Almost surely, 225550100131 is an apocalyptic number.

25550100131 is a deficient number, since it is larger than the sum of its proper divisors (323419069).

25550100131 is an equidigital number, since it uses as much as digits as its factorization.

25550100131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 323419068.

The product of its (nonzero) digits is 750, while the sum is 23.

Adding to 25550100131 its reverse (13100105552), we get a palindrome (38650205683).

The spelling of 25550100131 in words is "twenty-five billion, five hundred fifty million, one hundred thousand, one hundred thirty-one".

Divisors: 1 79 323418989 25550100131