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2555552022103 = 8213112730843
BaseRepresentation
bin100101001100000010110…
…001010011111001010111
3100001022022210222200100201
4211030002301103321113
5313332232304201403
65234000540521331
7352426650530503
oct45140261237127
910038283880321
102555552022103
118a5892547753
12353349250247
13156cab77b432
148b99191d303
1546720aee21d
hex25302c53e57

2555552022103 has 4 divisors (see below), whose sum is σ = 2558664753768. Its totient is φ = 2552439290440.

The previous prime is 2555552022047. The next prime is 2555552022137. The reversal of 2555552022103 is 3012202555552.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2555552022103 - 241 = 356528766551 is a prime.

It is a super-2 number, since 2×25555520221032 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2555552022203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1556364601 + ... + 1556366242.

It is an arithmetic number, because the mean of its divisors is an integer number (639666188442).

Almost surely, 22555552022103 is an apocalyptic number.

2555552022103 is a deficient number, since it is larger than the sum of its proper divisors (3112731665).

2555552022103 is an equidigital number, since it uses as much as digits as its factorization.

2555552022103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3112731664.

The product of its (nonzero) digits is 150000, while the sum is 37.

Adding to 2555552022103 its reverse (3012202555552), we get a palindrome (5567754577655).

The spelling of 2555552022103 in words is "two trillion, five hundred fifty-five billion, five hundred fifty-two million, twenty-two thousand, one hundred three".

Divisors: 1 821 3112730843 2555552022103