Base | Representation |
---|---|
bin | 1011101000000001000111… |
… | …00010010101111011001111 |
3 | 10100111220202221121021021012 |
4 | 11310000203202111323033 |
5 | 11322321031314113210 |
6 | 130212014521155435 |
7 | 5245645510600244 |
oct | 564004342257317 |
9 | 110456687537235 |
10 | 25564241551055 |
11 | 8166808996149 |
12 | 2a4a63092bb7b |
13 | 113590b91946c |
14 | 64545cb4b5cb |
15 | 2e4eb7ec9305 |
hex | 174023895ecf |
25564241551055 has 4 divisors (see below), whose sum is σ = 30677089861272. Its totient is φ = 20451393240840.
The previous prime is 25564241551033. The next prime is 25564241551063. The reversal of 25564241551055 is 55015514246552.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 25564241551055 - 210 = 25564241550031 is a prime.
It is a super-2 number, since 2×255642415510552 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 25564241550994 and 25564241551012.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2556424155101 + ... + 2556424155110.
It is an arithmetic number, because the mean of its divisors is an integer number (7669272465318).
Almost surely, 225564241551055 is an apocalyptic number.
25564241551055 is a deficient number, since it is larger than the sum of its proper divisors (5112848310217).
25564241551055 is an equidigital number, since it uses as much as digits as its factorization.
25564241551055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5112848310216.
The product of its (nonzero) digits is 6000000, while the sum is 50.
The spelling of 25564241551055 in words is "twenty-five trillion, five hundred sixty-four billion, two hundred forty-one million, five hundred fifty-one thousand, fifty-five".
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