Base | Representation |
---|---|
bin | 1110111000101010110… |
… | …0110001000010011111 |
3 | 220110002021020010202012 |
4 | 3232022230301002133 |
5 | 13142213343431341 |
6 | 313251502421435 |
7 | 24322141441223 |
oct | 3561254610237 |
9 | 813067203665 |
10 | 255730061471 |
11 | 994aaa53245 |
12 | 4168b59187b |
13 | 1b166253b01 |
14 | c53d834783 |
15 | 69badd00eb |
hex | 3b8ab3109f |
255730061471 has 8 divisors (see below), whose sum is σ = 266239518864. Its totient is φ = 245409963840.
The previous prime is 255730061459. The next prime is 255730061479. The reversal of 255730061471 is 174160037552.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 255730061471 - 230 = 254656319647 is a prime.
It is a super-3 number, since 3×2557300614713 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255730061479) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47337185 + ... + 47342586.
It is an arithmetic number, because the mean of its divisors is an integer number (33279939858).
Almost surely, 2255730061471 is an apocalyptic number.
255730061471 is a deficient number, since it is larger than the sum of its proper divisors (10509457393).
255730061471 is an equidigital number, since it uses as much as digits as its factorization.
255730061471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94679881.
The product of its (nonzero) digits is 176400, while the sum is 41.
The spelling of 255730061471 in words is "two hundred fifty-five billion, seven hundred thirty million, sixty-one thousand, four hundred seventy-one".
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