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256020213 = 385340071
BaseRepresentation
bin11110100001010…
…00111011110101
3122211202011201010
433100220323311
51011020121323
641223222433
76226064421
oct1720507365
9584664633
10256020213
11121575859
12718a7a19
134106c967
1426005b81
1517722c93
hexf428ef5

256020213 has 4 divisors (see below), whose sum is σ = 341360288. Its totient is φ = 170680140.

The previous prime is 256020209. The next prime is 256020229. The reversal of 256020213 is 312020652.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 256020213 - 22 = 256020209 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 256020213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (256020253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42670033 + ... + 42670038.

It is an arithmetic number, because the mean of its divisors is an integer number (85340072).

Almost surely, 2256020213 is an apocalyptic number.

It is an amenable number.

256020213 is a deficient number, since it is larger than the sum of its proper divisors (85340075).

256020213 is an equidigital number, since it uses as much as digits as its factorization.

256020213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85340074.

The product of its (nonzero) digits is 720, while the sum is 21.

The square root of 256020213 is about 16000.6316437821. The cubic root of 256020213 is about 634.9771318774.

Adding to 256020213 its reverse (312020652), we get a palindrome (568040865).

The spelling of 256020213 in words is "two hundred fifty-six million, twenty thousand, two hundred thirteen".

Divisors: 1 3 85340071 256020213