Base | Representation |
---|---|
bin | 1011101001010110010101… |
… | …11100111001110111100111 |
3 | 10100200021212221011102001220 |
4 | 11310223022330321313213 |
5 | 11324043234443411210 |
6 | 130245023243151423 |
7 | 5252155450050516 |
oct | 564531274716747 |
9 | 110607787142056 |
10 | 25609999982055 |
11 | 818415a37a675 |
12 | 2a57481215573 |
13 | 113a0219b7738 |
14 | 64776000467d |
15 | 2e62952ccc70 |
hex | 174acaf39de7 |
25609999982055 has 16 divisors (see below), whose sum is σ = 40994449371744. Its totient is φ = 13652516856960.
The previous prime is 25609999982051. The next prime is 25609999982057. The reversal of 25609999982055 is 55028999990652.
It is not a de Polignac number, because 25609999982055 - 22 = 25609999982051 is a prime.
It is a super-3 number, since 3×256099999820553 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (25609999982051) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 384328084 + ... + 384394713.
It is an arithmetic number, because the mean of its divisors is an integer number (2562153085734).
Almost surely, 225609999982055 is an apocalyptic number.
25609999982055 is a deficient number, since it is larger than the sum of its proper divisors (15384449389689).
25609999982055 is a wasteful number, since it uses less digits than its factorization.
25609999982055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 768725026.
The product of its (nonzero) digits is 1417176000, while the sum is 78.
The spelling of 25609999982055 in words is "twenty-five trillion, six hundred nine billion, nine hundred ninety-nine million, nine hundred eighty-two thousand, fifty-five".
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